Array Questions
- Longest Continuous Increasing Subsequence
Question
Original Question: Leetcode 674. Longest Continuous Increasing Subsequence
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).
Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 
Solution
- Java
- Python
class Solution {
    public int findLengthOfLCIS(int[] nums) {
        if(nums.length == 0) return 0;
        int dp[] = new int[nums.length];
        dp[0] = 1;
        int res = 1;
        for(int i = 1; i < nums.length; i++){
            if(nums[i] > nums[i-1]){
                dp[i] = dp[i-1]+1;
            } else {
                dp[i] = 1;
            }
            res = Math.max(dp[i], res);
        }
        return res;
    }
}
class Solution(object):
    def findLengthOfLCIS(self, nums):
        if not nums:
            return 0
        dp = [1] * len(nums)
        for i in range(1, len(nums)):
            if nums[i] > nums[i-1]:
                dp[i] = dp[i - 1] + 1
        return max(dp)